Discussion about math, puzzles, games and fun. Useful symbols: ÷ × ½ √ ∞ ≠ ≤ ≥ ≈ ⇒ ± ∈ Δ θ ∴ ∑ ∫ π -¹ ² ³ °

You are not logged in.

- Topics: Active | Unanswered

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

.

Good attempt, Monox D. I-Fly!

CG#26. Find the equation of the straight line whose slope is -4 and passing through the point (1,2).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#27. Find the equation of the straight line whose slope is

and passing through (5, -4).It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#28. Using the concept of slope, show that the following set of points are collinear: (2, 3), (3, -1), and (4, -5).

It is no good to try to stop knowledge from going forward. Ignorance is never better than knowledge - Enrico Fermi.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#29. Using the concept of slope, show that the following set of points are collinear (4, 1), (-2, -3), and (-5, -5).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#30. Using the concept of slope, show that the following set of points are collinear (4, 4), (-2, 6), and (1, 5).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#31. Find the centroid of the triangle whose vertices are (1, 3), (2, 7), and (12, -16).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

.

CG#32. Find the centroid of the triangle whose vertices are (3, -5), (-7, 4), and (10, -2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#33. The center of a circle is at (-6, 4). If one end of a diameter of a circle is at the origin, find the other end.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#34.Using the section formula, show that the points A(1, 0), B(5, 3), C(2, 7), and D(-2, 4) are the vertices of a parallelogram taken in order.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#35. If the centroid of a triangle is at (1, 3) and two of its vertices are (-7, 6) and (8, 5), then find the third vertex of the triangle.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#35. (A) Find the coordinates of the point which divides the line segment joining (3, 4) and (-6, 2)in the ratio 3 : 2 externally.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#36. Find the equation of the straight line passing through the points (0, -6) and (-8, 2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#37. Find the equation of the straight line passing through the the point (3, 4) and has intercepts which are in the ratio 3 : 2.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#38. Find the equation of the straight lile passing through the point (5, -3) whose intercepts on the axes are equal in magnitude but opposite in sign.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#39. Find the equation of the line passing through the point (9, -1) and hiving its x-intercept thrice as its y-intercept.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#40. A straight line cuts the coordinate axes at A and B. If the midpoint of AB is (3, 2), then find the equation of the line.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#41. If the straight lines

and are parallel, find 'a'.Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#42. Find the value of a if the straight lines 5x - 2y - 9 = 0 and ay + 2x - 11 = 0 are perpendicular to each other.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#43. Find the equation of the straight line parallel to the line 3x - y + 7 = 0 and passing through the point (1, -2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#44. Find the equation of the straight line perpendicular to the staright line x - 2y + 3 = 0 and passing through the point (1, -2).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#45. If the vertices of ΔABC are A(2, -4), B(3, 3), and C(-1, 5), find the equation of the straight line along the altitude from the vertex B.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#46. If the vertices of

ABC are A(-4, 4), B(8, 4), and C(8, 10),find the equation of the straight line along the median from vertex A.Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#47. Find the coordinates of the foot of the perpendicular from the origin on the staright line 3x + 2y = 13.

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

CG#48. Find the midpoint of the line joining (a, -b) and (3a, 5b).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline

**ganesh****Administrator**- Registered: 2005-06-28
- Posts: 34,570

Hi,

.

CG#49. Find the centroid of the triangle with vertices (-2, -5), (-2, 12), and (10, -1).

Nothing is better than reading and gaining more and more knowledge - Stephen William Hawking.

Offline